Question 920664
Odd consecutive integers, 2n+1, 2n+3 for any Natural Number n.


{{{highlight_green(7(2n+1)=8+5(2n+3))}}}


The trouble with your equation compared to this one is that you used variable expressions that
would not ensure to be odd numbers.  You can now continue with the equation and solve for n
and then evaluate 2n+1 and 2n+3.