Question 920475
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Hi,
10&#960;/3 - 2&#960; = 4 &#960;/3  Step I for those > 2pi 
III Quadrant or  (-1/2,-&#8730;3/2 ) 
One may view these terminal points as MINUS those in the first Quadrant for &#960;/3    
terminal points (-1/2,-&#8730;3/2 )
sec 10&#960;/3 = 1/(-1/2) = -2
csc 10&#960;/3 = 1/(- &#8730;3/2) = -2/&#8730;3 = -2&#8730;3/3
..........
(cosx, sinx) Summary Unit Circle
*[illustration wheel_smaller.jpg].