Question 920453
Convert to vertex form by completing the square.
{{{h(x)=3x^2+9x-4}}}
{{{h(x)=3(x^2+3x)-4}}}
{{{h(x)=3(x^2+3x+9/4)-4-3(9/4)}}}
{{{h(x)=3(x+3/2)^2-16/4-27/4}}}
{{{h(x)=3(x+3/2)^2-43/4}}}
The vertex is (-3/2,-43/4).
The y-intercept is (0,-4)