Question 920346
Helicopter	speed	=x	mph					
wind speed given	speed	=y	mph					
against  	wind speed given	2	hours					
with	wind speed given	1 2/3	hours					
								
Distance against 		300	miles	distance with 		300	miles	
t=d/r	against	wind speed given		-				
300.00	/	(	x	-	y	)=	2.00	
2.00	(	x	-	y	)	=	1.67	
2.00	x	-	2.00	y	=	300.00	....................1	
								
300.00	/	(	x	+	y	)=	1.67	
1.67	(	x	+	y	)	=	300.00	
1.67	x	+	1.67	y	=	300.00	...............2	
Multiply (1) by	1.67							
Multiply (2) by	2.00							
we get								
3.33	x	+	-3.33	y	=	500.00		
3.33	x	+	3.33	y	=	600.00		
6.67	x	=	1100.00					
/	6.67							
x	=	165.00	mph					
								
plug value of x in (1)				y				
2.00	x		-2.00	y	=	300.00		
330.00			-2.00	-330.00	=	300.00		
-2.00	y	=	300.00					
-2.00	y	=	-30.00	mph				
	y	=	15.00					
Helicopter	speed	165.00	mph					
wind speed given	speed	15.00	mph					
								
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