Question 920172
{{{4x^2+4y^2-4x+8y=11}}}
{{{4x^2-4x+1+4y^2+8y+4=11+1+4}}}
{{{4(x^2-x+1/4)+4(y^2+2y+1)=16}}}
{{{4(x-1/2)^2+4(y+1)^2=16}}}
{{{(x-1/2)^2+(y+1)^2=4}}}
{{{(x-1/2)^2+(y+1)^2=2^2}}}
That is the equation of the circle centered at (1/2,-1) with radius 2.
{{{drawing(300,300,-5,5,-5,5,
grid(1),
red(circle(1/2,-1,2)),
red(circle(1/2,-1,0.1))
)}}}