Question 77842
In order for the following fraction to be defined, what value(s) can x not assume?

{{{7/((2/x)-(3/5))}}}
Lets look at the denominator({{{2/x-3/5}}}).  The LCM is 5x. To simplify, we will multiply both numerator and denominator of this term by 5x/5x and we get:

{{{(10-3x)/5x}}}-------------------Now we have:

{{{7/((10-3x)/5x)}}}  Now we will multiply the numerator and denominator by {{{5x/(10-3x)}}} Notice that this will make the denominator =1 and we get:

{{{(35x/(10-3x))/1}}} or {{{35x/(10-3x)}}}  Now we can see that

10-3x cannot equal zero, so 3x cannot equal 10 or x cannot equal (10/3)


Hope this helps---ptaylor