Question 920126
{{{f(x)=3sqrt(x+1)}}}


Finding inverse the quick way
{{{x=3sqrt(y+1)}}}
{{{x^2=9(y+1)}}}
{{{y+1=(1/9)x^2}}}
{{{y=-1+(1/9)x^2}}}
{{{highlight(y=(1/9)x^2+1)}}} with the restriction {{{highlight(x>=0)}}}.