Question 77856
The general equation of the line is given by: 


y = mx + b 


Where m is the slope and (x,y) is the co-ordinate point. 


Let us substitute the given slope and the point in the above equation. 


y = (3)x + b 


Now substituting the point, we have,


2 = (3)(4) + b 


2 = 12 + b 


2 - 12 = b 


b = -10 


Now, we substitute the "b" value and the slope to find the equation of the straight line.


y = 3x - 12


is the equation of the required line.


Hence, the solution.