Question 919867
Two different substitutions.


{{{y+x=5(1/6)}}}
{{{y+x=5/6}}}
-
{{{y=5xy-x}}}
{{{y=5(1/6)-x}}}
{{{y=5/6-x}}}
-
{{{highlight(x(5/6-x)=1/6)}}}

{{{6*x(5/6-x)=6(1/6)}}}

{{{5x-6x^2=6}}}

{{{-6x^2+5x-6=0}}}

{{{highlight(6x^2-5x+6=0)}}}

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