Question 10549
Use the substitution method to solve for x and y.  You must solve for one variable in one of the equations and substitute into the other equation.  I recommend you solve for y in the second equation, and substitute into the other one.


xy = 56
y-x =1, so y = x+1


xy = 56
x(____) = 56
x(x+1) = 56
{{{x^2 + x - 56=0}}}


Factor it:
(x+8)(x-7) = 0
x= -8;  x= 7


Substitute these values back into the simplest equation (take your pick!):

If x = -8, then y = x+1 =-8 + 1 = -7.

If x = 7, then y = x+1=7+1= 8


There are two points of solution:
(-8,-7) and (7,8)


R^2 at SCC