Question 919804
Find the values of the trigonometric functions of t from the given information. 
sec t = 2, sin t < 0 
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sec positive and sin negative means t is in QIV where x is pos and y is neg
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By definition sec = r/x
Since sec = 2, r = 2 and x = 1
Then y = -sqrt[2^2-1] = -sqrt(3)
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sin = y/r = -sqrt(3)/2
cos = x/r = 1/2
tan = y/x = -sqrt(3)/1 = -sqrt(3)
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csc = -2/sqrt(3)
sec = 2
cot = -1/sqrt(3)
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Cheers,
Stan H.
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