Question 919721
if cos theta = 1/3, theta is in Q IV, find the exact value of sin(theta+pie/3)
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By definition, cos = x/r
So x = 1 and r = 3
Then y = -sqrt(3^2-1^2] = -sqrt(8)
Therefore 
sin(t) = -sqrt(8)/3 = -(2/3)sqrt(2) 
and cos(t) = 1/3
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Ans:: sin(t + pi/3) = sin(t)cos(pi/3)+cos(t)sin(pi/3)
= -(2/3)sqrt(2)*(1/2) + (1/3)(sqrt(3)/2)
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= -sqrt(2)/3 + sqrt(3)/6
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= [sqrt(3) - 2sqrt(2)]/6
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Cheers,
Stan H.
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