Question 919721
 <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi
cos(&#952) = 1/3  Then  sin(&#952)= &#8730;2/3  Note: 1^2 + (&#8730;2)^2 = 3
sin(&#952; + &#960;/3) = sin&#952;cos(&#960;/3) + cos&#952;sin(&#960;/3)
sin(&#952; + &#960;/3) = (&#8730;2/3)cos(&#960;/3) + (1/3)sin(&#960;/3)
Plug and Play
sin(&#952; + &#960;/3) = (&#8730;2/3)(1/2) + (1/3)(&#8730;3/2) &#61608; &#61629;
............
&#61617;&#61613;&#952;	radians	sin &#952;	cos &#952;	tan &#952;
0°	0	0	1	0
30°	&#960;/6	1/2	&#8730;3/2	&#8730;3/3
45°	&#960;/4	&#8730;2/2	&#8730;2/2	1
60°	&#960;/3	&#8730;3/2	1/2	&#8730;3
90°	&#960;/2	1	0	&#9472;
 &#61607; &#61629;&#61617;&#61613; &#61608; &#61613;&#61623;&#61618; &#61607;