Question 919612
Lets let n = the first of our odd numbers.  Then notice that the odd numbers increase by 2.  So the next consecutive odd number would be n+2. And the third consecutive odd number would be n+2+2 = n+4.<br>

Now we know from what we're trying to find that the sum of the first and second consecutive odd number plus 3 times the third odd number is 99.  So writing this as an equation we get:<br>

n+n+2+3(n+4)=99<br>

Now we can solve that equation:<br>

n+n+2+3(n+4)=99 Distribute the 3
n+n+2+3n+12=99 Combine like terms
5n+14=99  Subtract 14 from both sides
5n = 85 divide both sides by 5
n = 17<br>

Now we know that our first odd number is 17.  Plugging back into our expressions for the second and third consecutive odd numbers we get 17+2 and 17+4 or 19 and 21 respectively.