Question 919718
 <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi
cos(&#8722; &#960;/4)  = cos(&#960;/4) = &#8730;2/2
 csc(&#8722;&#960;/4) = 1/sin(&#8722;&#960;/4) = -1/sin(&#960;/4) = {{{-1/(sqrt(2)/2)}}} = -&#8730;2
 cot(&#8722;&#960;/4) =  1 /tan(-&#960;/4) =  -1/tan(&#960;/4)  = -1
..............
&#952;	radians	sin &#952;	cos &#952;	tan &#952;
0°	0	0	1	0
30°	&#960;/6	1/2	&#8730;3/2	&#8730;3/3
45°	&#960;/4	&#8730;2/2	&#8730;2/2	1
60°	&#960;/3	&#8730;3/2	1/2	&#8730;3
90°	&#960;/2	1	0	&#9472;