Question 919597
In lowercase instead,
{{{p/(p-2)+4/(p-1)=5}}}, only a best-guess what you meant.


{{{((p-2)(p-1))(p/(p-2)+4/(p-1))=((p-2)(p-1))5}}}


{{{p(p-1)+4(p-2)=5(p^2-3p+2)}}}


{{{p^2-p+4p-8=5p^2-15p+10}}}


{{{-4p-8=4p^2-15p+10}}}


{{{4p^2-11p+18=0}}}


The solutions are complex but not real.
{{{highlight(p=(11+- i*sqrt(133))/8)}}}