<PRE><B>Question 919590</B>
The area of A certain triangle is 56inches^2. The altitude of the triangle measures two inches less than double the measure of the base of that triangle. Please use algebraic method to determine:
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height = 2*base-2
Area = (1/2)(base)(height)
56 = (1/2)(b)(2b-2)
56 = (1/2)b(2)(b-1)
56 = b(b-1)
b^2 -b - 56 = 0
(b-8)(b+7) = 0
Positive solution::
base = 8 inches
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(A) measures of altitude of triangle?
height = 2b-2 = 16-2 = 14 inches
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(B) measure of base of triangle.
base = 8 inches
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Cheers,
Stan H.
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