Question 919569
h=hundreds digit
t=tens digit
u=ones digit
h=t
h=2+u
19(t+h+u)=100u+10t+h
19(2+u+2+u+u)=100u+10(2+u)+2+u
19(3u+4)=100u+20+10u+2+u
57u+76=111u+22
54=111u-57u
54=54u
u=1
h=3
t=3
19(7)=100+30+3
133=133
100h+10t+u
300+30+1=331
The original number is 331