Question 919551

let positive numbers be {{{x}}} and {{{y}}}

if {{{x}}} is three times {{{y}}} we have:

{{{x=3y}}} .............eq.1

if the sum of the {{{x}}} and {{{y}}} is {{{36}}}, we have:

{{{x+y=36}}} ........eq.2

solve the system:

{{{x=3y}}} .............eq.1...substitute in eq.2
{{{x+y=36}}} ........eq.2
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{{{3y+y=36}}} ........eq.2...solve for {{{y}}}

{{{4y=36}}}

{{{y=36/4}}}

{{{highlight(y=9)}}}

go back to eq.1 and find {{{x}}}

{{{x=3y}}} .............eq.1

{{{x=3*9}}} 

{{{highlight(x=27)}}} 

so, your positive numbers are:{{{highlight(27)}}} and {{{highlight(9)}}}