Question 919160
4C2 = 6 PAIRINGS:  12,13,14,23,24,34
a) P(At least one of the top 2 candidates) = 1 - P(neither) = 1- 1/6 = 5/6
b) P(Both of the top 2 candidates) = 1/6
c) P(Neither of the top 2 candidates) = 1/6
P(A|B) = P(A and B)/P(B)
d) P(3 |2) =  {{{(1/6)/(3/6)}}} = 1/3

e) P(3 0r 4 |2) = {{{(2/6)/(3/6)}}} = 2/3