Question 919302
Log 81 = 2Log 9 = 2(.954)
 Log 9 over 2 = .954/.301
 Log √2 = (1/2)Log 2 = .954/2
 Log 2 over 9 = .301/.954
 Log 2304 = Log 256 + Log 9 = 8Log 2 + Log 9 = 8(.301) + .954
 Log 18 = Log 2 + Log 9 = .301 + .954
.........
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]