Question 919112
The man wants cost and revenue to be equal.


Cost:  {{{x(y/100)}}} in units of "rand".  The man now has x loaves.


Revenue:  Man has {{{(5/6)x}}} loaves because he gave {{{1/6}}} to charity.
{{{(5/6)x*p}}}, the revenue of this bread to be sold.


{{{x(y/100)=(5/6)xp}}}
Solve for p.



{{{y/100=(5/6)p}}}


{{{(6/5)(y/100)=p}}}


{{{p=(3y)/(5*50)}}}


{{{highlight(p=(3y)/250)}}}