Question 919205
log(x + 3) = 1 - log(x - 2)
log(x + 3) + log(x - 2) = 1
{{{log(10, (x+3)(x-2)) = 1}}}
(x+3)(x-2) = 10
x^2  + x - 6 = 10
x^2 + x -16 = 0
x = 3.53112887414927
 *[invoke quadratic "x", 1, 1,-16]