Question 919166
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}}
y = a(x+1)^2 - 4 
P(0,-3)
-3 = a(1)^2 - 4
1 = a

y = (x+1)^2 - 4
{{{drawing(300,300,   -6, 6, -6, 6, grid(1), blue(line(-1,6,-1,-6)) ,
circle(0, -3,0.2),
circle(-1, -4,0.2),
graph( 300, 300, -6, 6, -6, 6,0,(x+1)^2 - 4) )}}}