Question 918912
x, width of first plot
y, width of second plot


FIRST PLOT
{{{L=x/2}}} and therefore area is {{{(x/2)x=(1/2)x^2}}}.


SECOND PLOT
Length, {{{-3+15y}}} and area is {{{(15y-3)y}}}.


The areas of the two plots are given as equal:
{{{highlight((1/2)x^2=(15y-3)y)}}}