Question 918939
solve the equation for solutions in the interval from [0,360 degrees): sin(2 theta) +1=cos(2 theta)
-------
sin + 1 = cos = 1 - sin^2
sin^2 + sin - 1 = 0
x = sin(2theta)
x^2 + x - 1 = 0
---
*[invoke solve_quadratic_equation 1,1,-1]
============
x =~ 0.618034 = 2theta
2theta =~ 38.17, 321.83, 398.18, 681.83 degs
theta = 19.085, 160.91, 199.09, 340.91 degs