<PRE><B>Question 919009</B>
{{{ tan( ( 14*pi )/3 ) }}}
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You can step through this:
Note that {{{ ( 6*pi) /3 = 2*pi }}}
is a full 180 degree circle
bringing you back to 0 degrees
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{{{ ( 12*pi ) / 3  = 4*pi }}} is 2 full
circles which again brings you back to
0 degrees
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Note that {{{ ( 14*pi )/3 - ( 12*pi )/3 = ( 2*pi )/3 }}}
So, that makes the problem:
{{{ tan( ( 2*pi )/3 ) }}}
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This is more than {{{ pi/2 }}}, so the angle is in
the 2nd quadrant where the tan is negative (+)/(-)
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The angle made with the horizontal is {{{ pi/3 }}},
which is 60 degrees, so I can say:
{{{ tan( ( 14*pi )/3 ) = - sqrt(3)/1 }}}
{{{ tan( ( 14*pi )/3 ) = - sqrt(3) }}}
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Always do a drawing -it helps

 
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