Question 918916
{{{f(x)=(x-3)^2-2}}}

it's a parabola, opens upward

first find the vertex- a point where the parabola makes its sharpest turn
{{{k=-2}}}; so,the vertex is at ({{{3}}},{{{-2}}})

 from {{{f(x)=(x-3)^2-2}}} we see that {{{h=3}}} 

{{{ graph( 600, 600, -10, 10, -10, 10, (x-3)^2-2) }}}

the open interval on which the function is increasing:

looking at the vertex, parabola increasing from {{{x=3}}} to {{{infinity}}}

so, interval is:

({{{3}}},{{{infinity}}})