Question 918680
H0: mu = 10
H1: mu < 10 (since claim is weight loss is less)
Thus, Using a one tailed T Distribution
test statistic: t(8.6) = -1.4/(2.4/sqrt(14) = -2.18
critical value: invT(.05, 13) = -1.77
-2.18 < -.177
b) At a 5% significance level, the claim of the weight loss program is supported