Question 918709
There are four consecutive odd integers such that sum of the first and third integer is 166. What is the product of the 2nd and last integers?
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1st:: 2x-3
2nd:: 2x-1
3rd:: 2x+1
4th:: 2x+3
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Equation:
2x-3+2x+1 = 166
4x = 168
x = 42
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Ans: (2x-1)(2x+3 = 83*87 = 7221
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Cheers,
Stan H.
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