Question 918700
How to go about graphing y = sec(x/2)? 
How to find do I find the vertical and horizontal asymptotes and intercepts of that function?
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The easiest way to do this is::
1st:: Sketch a cosine curve.
2nd:: Label that curve so its period is 4pi
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3rd:: You have asymptotes at each point where cosine = 0
4th:: Where the cosine values are 1, sec(x/2) = 1
5th:: Since sec is inverse of cos, its curve increases
where cos decreases; its curve decreases where cos increases.
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{{{graph(400,400,-13,13,-4,4,cos(x/2),1/cos(x/2))}}}
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Cheers,
Stan H.
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