Question 918629
{{{3x^2-xy=0}}}
{{{x(3x-y)=0}}}
Two solutions
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.
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{{{x=0}}}
Then,
{{{2y-0=1}}}
{{{2y=1}}}
{{{y=1/2}}}
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{{{3x-y=0}}}
{{{3x=y}}}
and,
{{{2(3x)-5x=1}}}
{{{6x-5x=1}}}
{{{x=1}}}
{{{y=3(1)}}}
{{{y=3}}}
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(0,1/2) and (1,3)