Question 918647
{{{log(a, (x+6)/(x(x+2))) = 0}}}
a^0 = 1
{{{(x+6)/(x(x+2))= 1}}}
x+ 6 = x^2 + 2x
x^2 + x - 6 = 0
(x+3)(x-2) = 0   NOTE:  x = -3 is an extraneous root log(-3) invalid
x = 2