Question 918554


a wire {{{0.1in}}} in diameter {{{R}}} 
a wire is in shape of a cylinder, and we need to find a volume

{{{V=r^2*pi*h}}} where {{{h}}} is the length of a cylinder

since given diameter {{{R=0.1in}}} we can find radius using formula {{{r=R/2}}} 

{{{r=0.1in/2}}}

{{{r=0.05in}}} , then we have 

{{{V=(0.05in)^2*3.14*h}}}

{{{V=0.0025in^2*3.14*h}}}

{{{V=0.00785in^2*h}}}

since given dimensions of a block of copper and all will be used to make a wire, means that wire will have same volume as a block of copper;

so, find a volume of a block of copper:

{{{2in}}} by {{{4in}}} by {{{6in}}}

{{{V=2in*4in*6in}}}

{{{V=48in^3}}}

now plug it in {{{V=0.00785in^2*h}}}

{{{48in^3=0.00785in^2*h}}}.............solve for {{{h}}}

{{{48in^3/0.00785in^2=h}}}

{{{48in^cross(3)1/0.00785icross(n^2)=h}}}

{{{48in/0.00785=h}}}

{{{6114.65in=h}}} ......the length of a wire