Question 918427
Find the values of the trigonometric functions of t from the given information.
 cos t = − 12/13 
Terminal point of t is in Quadrant III where x is negative and y is negative
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By definition, cos(t) = x/r
So x = -12 and r = 13
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Solve for "Y"::
y = -sqrt[13^2 - 12^2] = -sqrt(25) = -5
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sin = y/r = -5/13
cos = x/r = -12/13
tan = y/x = -5/-12 = 5/12
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csc = r/y = -13/5
sec = r/x = -13/12
cot = x/y = 12/5
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Cheers,
Stan H.
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