Question 918306
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Let *[tex \Large \varphi] represent the measure of the original angle.  The supplement (note spelling for future postings) then measures *[tex \Large 180\ -\ \varphi].  The original angle is 18 degrees more than one-quarter of the supplement, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \varphi\ =\ \frac{180\ -\ \varphi}{4}\ +\ 18]


Solve for *[tex \Large \varphi] and then calculate *[tex \Large 180\ -\ \varphi]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \