Question 917828
{{{M(t)=t/(t^2+1)}}}
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{{{ARC=(M(4)-M(1))/(4-1)}}}
{{{ARC=(4/(4^2+1))-(1/(1^2+1))/(3)}}}

{{{ARC=(4/17-1/2)/3}}}
{{{ARC=(8/34-17/34)/3}}}
{{{ARC=(-9/34)/3}}}
{{{highlight(ARC=-3/34)}}}