Question 77656
{{{(2x^2 + 3)}}} = {{{(7x)}}}

{{{(2x^2-7x + 3)}}} = {{{(0)}}} [Isolate all of the terms to one side and set the equation equal to zero]
.

{{{(2x-1)(x-3))}}} = {{{(0)}}}  [factor]
(2x-1=0 [set each factor equal to zero and solve for x]
2x-1=0
2x=1
x=1/2
.
(x-3)=0
x-3=0
x=3
.
Check by plugging either value of x back into the original equation and solve.