Question 918057
{{{4^(4x-7)= 3^(9x-6)}}}



{{{(4x-7)log((4))=(9x-6)log((3))}}}
{{{4x*log((4))-7*log((4))=9x*log((3))-6*log((3))}}}
{{{9x*log((3))-4x*log((4))-6*log((3))=-7*log((4))}}}

{{{9x*log((3))-4x*log((4))=-7*log((4))+6*log((3))}}}
{{{x(9*log((3))-4*log((4)))=6*log((3))-7*log((4))}}}


{{{highlight(x=(6*log((3))-7*log((4)))/(9*log((3))-4*log((4))))}}}



You can use any logarithm base you want, and finish the computation.