Question 917957
What are the trigonometric functions if sin t= (-1/4). sec t<0
reference angle t is in quadrant III in which sin<0, cos<0.
sin(t)=-1/4 (given)
cos(t)=-&#8730;(1-sin^2(t))=-&#8730;(1-(-1/4)^2)=-&#8730;(1-(1/16))=-&#8730;(15/16=-&#8730;15/4
tan(t)=sin/cos=-1/-&#8730;15=&#8730;15/15
cot(t)=&#8730;15
csc(t)=-4
sec(t)=4/-&#8730;15=-4&#8730;15/15