Question 917703
Use Cramer's rule,
{{{A=(matrix(3,3,3,-2,4,1,1,1,6,-2,-3))}}}
{{{abs(A)=-53}}}
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{{{A[x]=(matrix(3,3,
4,-2,4,
3,1,1,
10,-2,-3))}}}
{{{abs(A[x])=-106}}}
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{{{A[y]=(matrix(3,3,
3,4,4,
1,3,1,
6,10,-3))}}}
{{{abs(A[y])=-53}}}
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{{{A[z]=(matrix(3,3,
3,-2,4,
1,1,3,
6,-2,10))}}}
{{{abs(A[z])=0}}}
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{{{x=abs(A[x])/abs(A)=(-106)/(-53)=2}}}
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{{{y=abs(A[y])/abs(A)=(-53)/(-53)=1}}}
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{{{a=abs(A[a])/abs(A)=(0)/(-53)=0}}}
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