Question 917741
How much of the silver alloy is wanted?


R, grams of silver alloy wanted....?

Try using ALL of the 65% and find how much of the 96.85% to add to it?

{{{(6500*65+h*96.85)/(6500+h)=73}}}; if h is a reasonable value, then you have enough of the higher content silver material.


{{{6500*65+96.85h=73(h+6500)}}}
{{{6500*65+96.85h=73h+6500*73}}}
{{{96.85h-73h=6500*73-6500*65}}}
{{{23.85h=8*6500}}}
{{{h=8*6500/23.85}}}
{{{h=2180}}}----Too high for the amount available.


Try the other way or, how much mixture is wanted?



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NEW INFORMATION


The question was really this instead:
<i>How much, u, of the 65% silver metal to mix with 1300 grams of the 96.85% silver metal
to make 73% silver?</i>


{{{highlight_green((65u+(96.85)(1300))/(u+1300)=73)}}}


Solve for u.