Question 917705
I don't understand what to do. The perimeter of a rectangle is 40 inches. Find the dimensions if the length is 2 inches less than twice the width. Please help me solve it. I did let steps like x=the width and 2x-2= the length but I don't know if that is correct.
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You are correct!! However, you failed to create the perimeter-equation.

Width = x, and length = 2x - 2
2(width + length) = perimeter, so: 2(x + 2x - 2) = 40
2(3x - 2) = 40
Solve for x to get the width, and substitute that value into the length-value expression to obtain the length.