Question 917599
{{{4/(y+2) = 1 - 8/(y(y+2)) }}}

{{{4 = (1 - 8/(y(y+2)))(y+2) }}}

{{{4 = 1(y+2) - (8/(y(y+2)))(y+2) }}}

{{{4 = 1(y+2) - (8/(y*cross((y+2))))cross((y+2)) }}}

{{{4 = y+2 - 8/y }}}

{{{4-2 = y - 8/y }}}

{{{2 = (y^2 - 8)/y }}}

{{{2y = y^2 - 8 }}}

{{{0 = y^2 -2y-8 }}}

{{{ y^2 -4y+2y-8 =0}}}

{{{ (y^2 -4y)+(2y-8) =0}}}

{{{ y(y -4)+2(y-4) =0}}}

{{{(y+2)(y-4)=0}}}

solutions:

if {{{y+2=0}}} =>{{{y=-2}}}

if {{{y-4=0}}}=>{{{y=4}}}