Question 917460
 x+8=2(y+3)^2  y-intercepts (x = 0)
4 = (y+3)^2
± 2 = y+3
-3 ±2 = y
y is -1, -5
distance between (0,-1) and (0,-5) = 4
{{{drawing(300,300,   -10,10,-10,10,   
 grid(1),
circle(0, -1,0.4),
circle(0,-5,0.4),
graph( 300, 300, -10,10,-10,10,0, sqrt(.5x+4) - 3,-sqrt(.5x+4) - 3 ))}}}