Question 917421
{{{4x^2+4y^2=64 }}}



circle

a. write the equation in standard form

 {{{(x - h)^2 + (y - k)^2 = r^2}}}


{{{4x^2/4+4y^2/4=64/4 }}}


{{{x^2+y^2=16 }}}


{{{(x-0)^2+(y-0)^2=16 }}}


b. Name the conic section
circle

c. Name the center

({{{0}}},{{{0}}})


{{{ graph( 600, 600, -10, 10, -10, 10, sqrt(-x^2+16),-sqrt(-x^2+16)) }}}