Question 917349
y^2 -2x = 2x -3
add 2x to both sides of =
y^2 = 4x - 3
square root of both sides of =
y = square root(4x -3)
this is a parabola with a real part and an imaginary part
calculate the first derivative
dy/dx = (1/2) * (4x-3)^(1/2)
set first derivative to 0
(1/2) * (4x-3)^(1/2) = 0
multiply both sides of = by 2
(4x-3)^(1/2) = 0
square both sides of = 
4x -3 = 0
x = 3/4
substitute x = 3/4 in y^2 = 4x - 3
y = 0
therefore the min point is
(3/4, 0)