Question 917283
The center on the x-axis and those two given points form an isosceles triangle, and the x-coordinate of the center of the circle should be in the middle of x=8 and x=3.


That center has y=0, because the point is given as ON THE x-AXIS.  


Center is the point (5,0).


Use either of the given points and Distance Formula to calculate and then compute the radius of the circle.  


Now just fill-in the necessary values for the standard form equation of  a circle.


{{{sqrt((8-5)^2+(3-0)^2)}}}
{{{sqrt((3)^2+(3)^2)}}}
{{{sqrt(18)}}}


When you square that, you have 18, which is {{{r^2}}} for the standard form equation.


{{{highlight((x-5)^2+y^2=18)}}}