Question 77592
Directions: Complete the table, and describe the resulting graphs by identifying the vertex point, the graph’s direction, and any axis intercepts gleaned from the table or graph. 
y = x^2-4x 
If x=0, y=0
If x=1, y=-3
If x=-1,y=5
If x=2,y=-4
If x=-2,y=12
{{{graph(400,300,-10,10,-10,10,x^2-4x)}}}
Vertex is at x=-b/2a= 4/2=2, y=-4
Graph opens up.
x-intercepts:
If y=0, x^2-4x=0
x(x-4)=0
x=0 or x=4
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Problem # 30
Directions: find the x-intercepts
y = x^2+x-6
Let y=0
x^2+x-6=0
(x+3)(x-2)=0
x=-3 or x=2 
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{{{graph(400,300,-10,10,-10,10,x^2+x-6)}}}

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Cheers,
stan H.