Question 916909

Help me solve this problem please:
The height of a triangle is 4 cm more than twice the length of the base. The area of the triangle is 35 cm(squared). Find the height of the triangle.
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Let height be H
Then base-length = {{{(H - 4)/2}}}
Since area = 35, then we can say that: {{{(1/2)(H)((H - 4)/2) = 35}}}
{{{(H(H - 4))/4 = 35}}}
{{{H^2 - 4H = 140}}}} ----- Cross-multiplying
{{{H^2 - 4H - 140 = 0}}}
(H - 14)(H + 10) = 0
H, or height = {{{highlight_green(14)}}} cm               OR              {{{H = - 10}}} (ignore)